A) 10 cm, 10 cm
B) 15 cm, 5 cm
C) 18 cm, 2 cm
D) 11 cm, 9 cm
Correct Answer: C
Solution :
Given, Magnification \[=\frac{{{f}_{0}}}{{{f}_{e}}}=9\]and \[{{f}_{0}}+{{f}_{e}}=20\] \[{{f}_{o}}=9{{f}_{e}}\] So, \[9{{f}_{e}}+{{f}_{e}}=20\] \[{{f}_{e}}=2\,cm\] \[{{f}_{o}}=9\times 2\] \[\therefore \] \[{{f}_{o}}=18\,cm\] Hence, the correction option is [c].
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