A) \[{{N}_{4}}\]and\[N{{H}_{4}}Cl\]
B) \[NC{{l}_{3}}\]and\[HCl\]
C) \[{{N}_{2}}\]and\[HCl\]
D) \[NC{{l}_{3}}\]and\[N{{H}_{4}}Cl\]
Correct Answer: B
Solution :
\[N{{H}_{3}}+3C{{l}_{2}}\to NC{{l}_{3}}+3HCl\] Here \[NC{{l}_{3}}\]is an explosive material. Hence, the correct option is (b).
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