A) 6%
B) 3%
C) 7%
D) 5%
Correct Answer: A
Solution :
Here, mass of a body,\[M=5\text{ }00\pm 0.05\text{ }kg\] Volume of a body \[V=100\pm 0.05\,{{m}^{3}}\] Density, \[\rho =\frac{M}{V}\] Relative error in density is \[\frac{\Delta \rho }{\rho }=\frac{\Delta \Mu }{M}+\frac{\Delta V}{V}\] Percentage error in density is \[\frac{\Delta \rho }{\rho }\times 100=\frac{\Delta M}{M}\times 1000+\frac{\Delta V}{V}\times 100\] \[=\left( \frac{0.05}{5}\times 100 \right)+\left( \frac{0.05}{1}\times 100 \right)=1%+5%=6%\] Hence, the correction option is [a].
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