NEET Sample Paper NEET Sample Test Paper-16

  • question_answer 72) The number of atoms in 4.25 g of\[N{{H}_{3}}\] is

    A) \[2.054\times {{10}^{23}}\]            

    B) \[5.043\times {{10}^{25}}\]

    C)      \[8.044\times {{10}^{23}}\]

    D)      \[6.023\times {{10}^{23}}\]                        

    Correct Answer: D

    Solution :

    As 1 mole of \[\text{N}{{\text{H}}_{3}}=17\,g.\] =1 mole of \[N{{H}_{3}}\]contains number of atoms \[4\times 6.023\times {{10}^{23}}\] So, number of atoms in 4.25 g of total             \[N{{H}_{3}}=\frac{4\times 6.023\times {{10}^{3}}}{17}\] \[=6.023\times {{10}^{23}}.\] Hence the correct option is (d).

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