A) Azoxybenzene
B) Azobenzene
C) Benzene
D) Aniline
Correct Answer: D
Solution :
\[\underset{\text{Nitrobenzene}}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,+6[H]\xrightarrow{Zn-HCl}\underset{\text{Aniline}}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,+2{{H}_{2}}O\] Hence, the correct option is (d).
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