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NEET Sample Paper NEET Sample Test Paper-16

  • question_answer
    In a hydrogen atom, the electron is in nth excited state. It comes down to first excited state by emitting ten different wavelengths. The value of n is

    A) 6                     

    B) 7                     

    C)      8                   

    D)      9

    Correct Answer: A

    Solution :

    Number of possible emission lines are \[n(n-1)/2\] When electron jumps from \[nth\] state to ground state. For this question, this value should be\[\frac{(n-1)(n-2)}{2}\] Hence, \[\frac{(n-1)(n-2)}{2}=10\] Solving we get n = 6. Hence, the correction option is (a).


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