NEET Sample Paper NEET Sample Test Paper-16

  • question_answer Heat of neutralization of strong acid and strong base is constant and equal to

    A)  8.7 kcal                      

    B)  13.7 kcal        

    C)       23.7 kcal         

    D)       30.7 kcal                    

    Correct Answer: B

    Solution :

    The heat of neutralization for strong acid and strong base is constant and is equal to -13.7 kcal. It involves the combination of\[{{\text{H}}^{\text{+}}}\]and \[O{{H}^{-}}\]ions to form unionized water. \[H+C{{l}^{-}}+N{{a}^{+}}+O{{H}^{-}}\to N{{a}^{+}}+C{{l}^{-}}+{{H}_{2}}O\] or \[{{H}^{+}}+O{{H}^{-}}\to {{H}_{2}}O\] Hence it is also known as heat of formation of water. Hence, the correct option is (b).

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