• # question_answer Heat of neutralization of strong acid and strong base is constant and equal to A)  8.7 kcal                      B)  13.7 kcal        C)       23.7 kcal         D)       30.7 kcal

The heat of neutralization for strong acid and strong base is constant and is equal to -13.7 kcal. It involves the combination of${{\text{H}}^{\text{+}}}$and $O{{H}^{-}}$ions to form unionized water. $H+C{{l}^{-}}+N{{a}^{+}}+O{{H}^{-}}\to N{{a}^{+}}+C{{l}^{-}}+{{H}_{2}}O$ or ${{H}^{+}}+O{{H}^{-}}\to {{H}_{2}}O$ Hence it is also known as heat of formation of water. Hence, the correct option is (b).