NEET Sample Paper NEET Sample Test Paper-16

  • question_answer A spring of force constant 800 N/m has an extension of 5 cm. The work done in extending it from 5 cm to 15 cm is

    A) 16 J                

    B) 8 J                  

    C)      32 J                

    D)      24 J                

    Correct Answer: B

    Solution :

    \[\Delta W=\frac{1}{2}k(x_{2}^{2}-x_{1}^{2})=\frac{1}{2}\times 800({{15}^{2}}-{{5}^{2}})\times {{10}^{-4}}=8J\]Hence, the correction option is (b).

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