• question_answer Two condensers of capacity C and 2C are connected in parallel and are charged to a potential difference V. If now the battery is removed and a material of dielectric constant K is placed between the plates of condenser of capacity C, then the potential difference across the condensers will be A) $\frac{3V}{K+2}$                B) $3V(K+2)$    C)      $\frac{K+2}{3V}$    D)      $\frac{3(K+2)}{V}$

The total quantity of charge on the system remains constant after disconnecting the battery $q=3CV=(KC+2C)V'$ $\therefore$    $V'=\frac{3V}{K+2}$ Hence, the correction option is (a).