question_answer

To get an output Y = 1 from the circuit shown in the figure, the input must be

A) A-0      B-1      C-0

B) A-0      B-0      C-1

C) A-1      B-0      C-1

D) A-1      B-0      C-0

Correct Answer: C

Solution :

Gate I is OR gate, \[Y'=A+B\] Gate II is and gate, \[Y=Y'.C\] \[\therefore \] \[A=1,B=0,C=1\] will give \[Y=1\] Hence, the correction option is (c).