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NEET Sample Paper NEET Sample Test Paper-15

  • question_answer
    \[{{\,}_{12}}{{A}^{27}}+{{\,}_{2}}H{{e}^{4}}\to {{\,}_{14}}S{{i}^{30}}+{{\,}_{1}}{{H}^{1}}+Q\]Mass of\[{{\,}_{13}}A{{l}^{27}}=26.9815\]amu and mass  of \[{{\,}_{14}}S{{i}^{30}}=29.9738.\]The Q is equal to

    A)  2.329 MeV                 

    B)  3.298 MeV

    C)  12.98 MeV                 

    D)  5.478 MeV

    Correct Answer: A

    Solution :

    The sum of the masses of product = 29.9738 + 1.0078 = 30.9816 amu. The sum of the masses of reactants = 26.9815 + 4.0026 = 30.9841 amu. Difference in their masses \[(\Delta \Mu )\] = 30.9816 - 30.9841 = -0.0025 amu. Here the value of Q is +ve. So \[Q=+0.0025\times 931.5\] = +2.329 MeV Hence, the correct option is [a].


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