NEET Sample Paper NEET Sample Test Paper-14

  • question_answer ) Identify the product in the reaction\[PhC\equiv CMe\xrightarrow{{{H}_{3}}{{O}^{+}},H{{g}^{2+}}}\]

    A) \[PhCOC{{H}_{2}}C{{H}_{3}}\] 

    B) \[PhC{{H}_{2}}C{{H}_{2}}CHO\]

    C) \[PhCOCOMe\]                      

    D) \[PhC{{H}_{2}}COC{{H}_{3}}\] 

    Correct Answer: A

    Solution :

    Due to higher stability of this cation \[[Ph-\overset{\oplus }{\mathop{C}}\,=CMe]\]than methyl cation, the\[-O{{H}^{o-}}\] will attack on the benzylic cation. \[\therefore \]\[PhCOC{{H}_{2}}C{{H}_{3}}\] would be the major product. Hence, the correct option is [a].

adversite



LIMITED OFFER HURRY UP! OFFER AVAILABLE ON ALL MATERIAL TILL TODAY ONLY!

You need to login to perform this action.
You will be redirected in 3 sec spinner

Free
Videos