• # question_answer ) Identify the product in the reaction$PhC\equiv CMe\xrightarrow{{{H}_{3}}{{O}^{+}},H{{g}^{2+}}}$ A) $PhCOC{{H}_{2}}C{{H}_{3}}$ B) $PhC{{H}_{2}}C{{H}_{2}}CHO$C) $PhCOCOMe$                      D) $PhC{{H}_{2}}COC{{H}_{3}}$

Due to higher stability of this cation $[Ph-\overset{\oplus }{\mathop{C}}\,=CMe]$than methyl cation, the$-O{{H}^{o-}}$ will attack on the benzylic cation. $\therefore$$PhCOC{{H}_{2}}C{{H}_{3}}$ would be the major product. Hence, the correct option is [a].