A) \[_{92}N{{p}^{238}}\]
B) \[_{90}T{{h}^{234}}\]
C) \[_{91}p{{a}^{234}}\]
D) \[{{\,}_{92}}{{U}^{234}}\]
Correct Answer: B
Solution :
\[_{92}^{238}U\overset{\alpha -decay}{\mathop{\to }}\,{}_{90}^{234}Th+_{2}^{4}He\] Hence, the correct option is [b].
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