• # question_answer The hybridization in $[Co{{(N{{H}_{3}})}_{6}}^{3+}]$is A) $ds{{p}^{3}}$                               B) $s{{p}^{3}}{{d}^{2}}$C) $s{{p}^{3}}$                                 D) ${{d}^{2}}s{{p}^{3}}$

Solution :

As $\text{N}{{\text{H}}_{\text{3}}}$is a strong ligand and the coordination number is 6, so the hybridization is${{d}^{2}}s{{p}^{3}}.$ Hence, the correct option is [d].

You need to login to perform this action.
You will be redirected in 3 sec