A) \[1.4\times {{10}^{-8}}M\]
B) \[1.2\times {{10}^{-4}}M\]
C) \[1.9\times {{10}^{-4}}M\]
D) \[3.7\times {{10}^{-4}}M\]
Correct Answer: B
Solution :
\[\alpha =\sqrt{{{K}_{a}}V}\] \[{{K}_{a}}=3.5\times {{10}^{-8}},V=\frac{1}{0.40}L=2.5L.\] \[\alpha =\sqrt{3.5\times {{10}^{-8}}\times 2.5}\] \[=2.95\times {{10}^{-4}}\] \[[{{H}^{+}}]=\frac{\alpha }{V}=\frac{2.95\times {{10}^{-4}}}{2.5}=1.18\times {{10}^{-14}}\] \[\approx 1.2\times {{10}^{-4}}M\] Hence, the correct option is [b].
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