A) Its volume will become greater by a factor of 2.5.
B) Its volume will become greater by, a factor of 1.6.
C) Its volume will become greater by a factor of 1.1.
D) Its volume will become smaller by a factor of 0.70.
Correct Answer: B
Solution :
\[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{f}}}{{{T}_{2}}}\] \[{{V}_{f}}=\frac{{{P}_{1}}{{T}_{2}}}{{{P}_{2}}{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{f}}}{{{T}_{2}}}\] \[{{V}_{f}}=\frac{{{P}_{1}}{{T}_{2}}}{{{P}_{2}}{{T}_{1}}}.{{V}_{f}}\] \[{{V}_{i}}=\]Volume of water bubble under water \[{{V}_{f}}=\] Volume of water bubble at the surface \[{{V}_{f}}=\frac{1.5\times 298{{V}_{i}}}{1\times 288}.\] \[=\frac{447}{228}{{V}_{i}}\] The volume becomes greater by a factor of 1.6. Hence, the correct option is [b].
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