NEET Sample Paper NEET Sample Test Paper-14

  • question_answer A 0.010 M solution of maleic acid, a monoprotic organic acid is 14 per cent ionized. What is the\[{{K}_{a}}\]for maleic acid?

    A) \[2.3\times {{10}^{-3}}\]                

    B) \[2.3\times {{10}^{-4}}\]

    C) \[2.0\times {{10}^{-4}}\]                

    D) \[2.0\times {{10}^{-6}}\]       

    Correct Answer: B

    Solution :

    Degree of dissociation, \[\alpha =\frac{14}{100}=0.14.\] Concentration of the maleic acid, C = 0.010 M. The equilibrium reaction is Hence, the correct option is .
    \[t=0\] \[C\] 0 0
    \[{{t}_{eq}}\] \[C(1-\alpha )\] \[C\alpha \] \[C\alpha \]
    \[{{K}_{a}}=\frac{{{C}^{2}}{{\alpha }^{2}}}{C(1-\alpha )}=\frac{C{{\alpha }^{2}}}{(1-\alpha )}\] \[{{K}_{a}}=\frac{0.010\times 0.14\times 0.14}{0.86}\] \[{{K}_{a}}=2.3\times {{10}^{-4}}.\] Hence, the correct option is [b].


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