NEET Sample Paper NEET Sample Test Paper-14

  • question_answer A vertical ring of radius r and resistance R falls vertically. It is in contact with two vertical rails, which are joined at the top. The rails are without friction and resistance. There is a horizontal uniform magnetic field of magnitude B perpendicular to the plane of the ring and the rails. When the speed of the ring is v, the current in the section PQ is

    A)  0                                

    B)  \[\frac{2Brv}{R}\]

    C)  \[\frac{4Brv}{R}\]                 

    D)  \[\frac{8Brv}{R}\]

    Correct Answer: D

    Solution :

    When a ring moves in a magnetic field perpendicular to its plane, replace the ring by a diameter perpendicular to the direction of motion. The emf is induced across this diameter. Induced emf \[e=B(2r)v\] Resistance of each half of ring\[=R/2\] As these are in parallel, the equivalent resistance = R/4 Current in the circuit\[=\frac{B(2r)v}{R/4}=\frac{8Brv}{R}\] Hence, the correction option is [d].


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