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NEET Sample Paper NEET Sample Test Paper-14

  • question_answer
    A cannot engine working between 300 K and 600 K has a work output of 800 J/cycle. The amount of heat energy supplied to the engine from the source in each cycle is

    A)  800 J             

    B)  1600 J

    C)  3200 J                       

    D)  6400 J

    Correct Answer: B

    Solution :

    Efficiency\[=\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{300}{600}=0.5\] \[\eta =\frac{\text{Work}\,\text{done}}{\text{Heat}\,\text{supplied}}=\frac{W}{Q}\] Therefore, \[\frac{1}{2}=\frac{800}{Q},\,\therefore \,Q=1600\,J\] Hence, the correction option is [b].


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