A) 3/4
B) 1/2
C) 1/4
D) All
Correct Answer: B
Solution :
Normal woman whose father was colour blind would have received the X chromosome from her father \[\to {{X}^{c}}X-\] marries a colour blind man \[-{{X}^{c}}Y\to \] their progeny. \[\begin{align} & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underset{\downarrow }{\mathop{{{X}^{c}}X\times {{X}^{c}}Y}}\, \\ & \text{Progeny}\,\,\,\underset{\begin{smallmatrix} colour\,blind \\ daughter \end{smallmatrix}}{\mathop{{{X}^{c}}{{X}^{c}}}}\,\,\,\underset{\begin{smallmatrix} normal \\ daughter \end{smallmatrix}}{\mathop{{{X}^{c}}X}}\,\,\,\underset{\begin{smallmatrix} colour\,blind \\ son \end{smallmatrix}}{\mathop{{{X}^{c}}Y}}\,\,\,\underset{normal\,son}{\mathop{XY}}\, \\ \end{align}\]
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