A) \[2N{{O}_{2}}(g)\rightleftharpoons {{N}_{2}}(g)+{{O}_{2}}(g)\]
B) \[S{{O}_{2}}(g)+N{{O}_{2}}(g)\rightleftharpoons S{{O}_{3}}(g)+NO(g)\]
C) \[{{I}_{2}}(g)+{{H}_{2}}(g)\rightleftharpoons 2HI(g)\]
D) \[2C(s)+{{O}_{2}}(g)\xrightarrow{{}}2CO(g)\]
Correct Answer: D
Solution :
\[\Delta {{n}_{g}}=0,\]then \[{{K}_{p}}={{K}_{c}}\] If \[\Delta {{n}_{g}}=+ve,\]then \[{{K}_{p}}>{{K}_{c}}\] If \[\Delta {{n}_{g}}=-ve,\]then \[{{K}_{p}}<{{K}_{c}}\] \[\Delta {{n}_{g}}={{n}_{p}}-{{n}_{r}}\]in gaseous state For [d] \[\Delta n=1\]
You need to login to perform this action.
You will be redirected in
3 sec
