NEET Sample Paper NEET Sample Test Paper-13

  • question_answer
    Percentage of Se in peroxidase anhydrase enzyme is 0.5% by weight (at. wt. = 78.4), then minimum molecular weight of peroxidase anhydrase enzyme is:

    A) \[1.568\times {{10}^{3}}\]                   

    B)  15.68

    C) \[1.568\times {{10}^{4}}\]                   

    D) \[2.136\times {{10}^{4}}\]

    Correct Answer: C

    Solution :

     Suppose the mol. wt. of enzyme \[=x\] Given 100 g of enzyme wt of Se = 0.5 gm \[\therefore \]In \[x\]g of enzyme wt. of Se \[=\frac{0.5}{1000}\times x\] Hence \[78.4=\frac{0.5\times x}{100}\] \[\therefore \]\[x=15680=1.568\times {{10}^{4}}\]


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