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NEET Sample Paper NEET Sample Test Paper-13

  • question_answer
    A 6 V battery is connected to the terminals of a three metre long wire of uniform thickness and resistance of \[100\Omega .\]The difference of potential, between two points on the wire separated by a distance or 50 cm, will be

    A)  2 V                             

    B)  3 V

    C)  1 V                             

    D)  1.5 V

    Correct Answer: C

    Solution :

    Total current drawn from the battery \[i=\frac{E}{R+r}=\frac{6}{100+0}=0.06A\] Resistance of 50 cm wire is \[R'=\frac{\rho l'}{A}=\left( \frac{\rho }{A} \right)l'\] \[=\left( \frac{R}{l} \right)l'\]                    \[\left( \because \,R=\frac{\rho l}{A} \right)\] \[=\frac{100}{300}\times 50\] So,       \[R'=\frac{50}{30}\Omega \] Hence, the potential difference between two points on the wire separated by a distance \[l'\]is \[V=iR'=0.06\times \frac{50}{3}=1\,V\]


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