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NEET Sample Paper NEET Sample Test Paper-12

  • question_answer
    A solid compound 'X' on heating gives \[C{{O}_{2}}\]gas and a residue. The residue mixed with water forms 'Y' on passing an excess of \[C{{O}_{2}}\]through 'Y' in water, a clear solution 'Z' is obtained. On boiling 'Z' compound, 'X' is reformed. The compound 'X' is

    A) \[Ca{{(HC{{O}_{3}})}_{2}}\]              

    B) \[CaC{{O}_{3}}\]

    C) \[N{{a}_{2}}C{{O}_{3}}\]                  

    D) \[{{K}_{2}}C{{O}_{3}}\]

    Correct Answer: B

    Solution :

     \[\underset{(x)}{\mathop{CaC{{O}_{3}}}}\,\xrightarrow{{}}CaO+C{{O}_{2}}\] \[CaO+{{H}_{2}}O\xrightarrow{{}}\underset{(Y)}{\mathop{Ca{{(OH)}_{2}}}}\,\] \[Ca{{(OH)}_{2}}+2C{{O}_{2}}\xrightarrow{{}}\underset{(Z)}{\mathop{Ca{{(HC{{O}_{3}})}_{2}}}}\,\] \[\underset{(Z)}{\mathop{Ca{{(HC{{O}_{3}})}_{2}}}}\,\xrightarrow{\Delta }\underset{(X)}{\mathop{CaC{{O}_{3}}}}\,+{{H}_{2}}O\]


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