A) \[C{{l}^{-}}+Cl{{O}^{-}}\]
B) \[C{{l}^{-}}+ClO_{2}^{-}\]
C) \[C{{l}^{-}}+ClO_{3}^{-}\]
D) \[C{{l}^{-}}+ClO_{4}^{-}\]
Correct Answer: A
Solution :
\[2NaOH+C{{l}_{2}}\to \underset{N{{a}^{+}}+C{{l}^{-}}}{\mathop{\underset{\downarrow }{\mathop{NaCl}}\,}}\,+\underset{N{{a}^{+}}+OC{{l}^{-}}}{\mathop{\underset{\downarrow }{\mathop{NaOCl}}\,}}\,+{{H}_{2}}O\]
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