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NEET Sample Paper NEET Sample Test Paper-11

  • question_answer
    Structure of a mixed oxide is cubic close-packed (ccp). The cubic unit cell of mixed oxide is com- posed of oxide ions. On fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is

    A) \[AB\,{{O}_{2}}\]                    

    B) \[{{A}_{2}}B{{O}_{2}}\]

    C) \[{{A}_{2}}{{B}_{3}}{{O}_{4}}\]                  

    D) \[A{{B}_{2}}{{O}_{2}}\]

    Correct Answer: D

    Solution :

     We know, in ccp If number of atoms = n Then number of octahedral voids = n and number of tetrahedral voids\[=2n\]
    \[\therefore \] \[{{A}^{2+}}\] \[{{B}^{+}}\] \[{{O}^{2-}}\]
    \[n\times 2\times \frac{1}{4}\] \[n\] \[n\]
    \[\frac{n}{2}\] \[n\] \[n\]
    1 2 2
    So, \[A{{B}_{2}}{{O}_{2}}.\]


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