A) Iron and \[{{H}_{2}}S{{O}_{4}}\](aqueous)
B) Iron and steam
C) Sodium and ethyl alcohol
D) Copper and HC1 (aqueous)
Correct Answer: D
Solution :
\[Fe+dil.{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}FeS{{O}_{4}}+{{H}_{2}}\uparrow \] \[3Fe+\underset{Stem}{\mathop{4{{H}_{2}}O}}\,\xrightarrow{{}}F{{e}_{3}}{{O}_{4}}+4{{H}_{2}}\] \[Cu+dil.HCl\xrightarrow{{}}No\,reaction\] Copper does not evolve\[{{H}_{2}}\]from acid as it is below hydrogen in electrochemical series. \[2Na+{{C}_{2}}{{H}_{5}}O{{H}_{4}}\xrightarrow{{}}2{{C}_{2}}{{H}_{5}}ONa+{{H}_{2}}\uparrow \]
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