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NEET Sample Paper NEET Sample Test Paper-11

  • question_answer
    A particle doing simple harmonic motion, amplitude = 4 cm, time period =12 sec. The ratio between time taken by it in going from its mean position to 2 cm and from 2 cm to extreme position is

    A)  1                                

    B)  1/3

    C)  1/4                              

    D)  1/2             

    Correct Answer: D

    Solution :

     \[\omega =\frac{2\pi }{T}=\frac{2\pi }{12}=\frac{\pi }{6}\frac{rad}{\sec }\] (For\[y=2\,cm\])\[2=4\left( \sin \frac{\pi }{6}{{t}_{1}} \right)\] By solving \[{{t}_{1}}=1\sec \]\[(For\,y=4\,cm){{t}_{2}}=3\sec \] So time taken by particle in going from 2 cm to extreme position is\[{{t}_{2}}-{{t}_{1}}=2\sec .\] Hence required ratio will be\[\frac{1}{2}.\]


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