A) 4 different gametes and 16 different zygotes
B) 8 different gametes and 16 different zygotes
C) 8 different gametes and 32 different zygotes
D) 8 different gametes and 64 different zygotes
Correct Answer: D
Solution :
A self-fertilizing trihybrid plant forms 8 different gametes and 64 different zygote. The genotype of trihybrid plant is AaBbCc. Number of gametes formed\[{{2}^{n}}={{2}^{3}}=8.\]Here n = no. ofheterozygosity = 3 in present case. No. of zygote formed\[{{8}^{2}}=64\]
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