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NEET Sample Paper NEET Sample Test Paper-11

  • question_answer
    The angular velocity of second's hand of a watch will be

    A) \[\frac{\pi }{60}rad/\sec \]                      

    B) \[\frac{\pi }{30}rad/\sec \]

    C) \[60\,\pi \,rad/\sec \]                   

    D) \[30\,\pi \,rad/\sec \]

    Correct Answer: B

    Solution :

     We know that second's hand completes its revolution \[(2\pi )\]in 60 sec \[\therefore \]      \[\omega =\frac{\theta }{t}=\frac{2\pi }{60}=\frac{\pi }{30}\,rad/\sec \]


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