A) \[P{{F}_{5}}\]
B) \[As{{F}_{5}}\]
C) \[Sb{{F}_{5}}\]
D) \[Bi{{F}_{5}}\]
Correct Answer: D
Solution :
Bismath \[(Bi)\] does not form pentafluorides due to inert pair effect i.e. reluctance of the 6s-elcctrons of \[Bi\] to participate in bond formation.
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