A) Metal ball suffers greater change in momentum
B) Rubber ball suffers greater change in momentum
C) The initial momentum of metal ball is greater than initial momentum of rubber ball
D) Both suffer same change in momentum
Correct Answer: B
Solution :
[b] The change in momentum in metal ball after the collision with a wall is \[\Delta P=m({{v}_{2}}-{{v}_{1}})=m(0-{{v}_{1}})=-m{{v}_{1}}\] The change in momentum in rubber wall is \[\Delta P'=m\,({{v}_{2}}'\,-\,{{v}_{1}})=m\,(-\,{{v}_{1}}-\,{{v}_{2}})=-\,2\,m\,{{v}_{1}}\] \[(\because \,\,{{v}_{2}}'={{v}_{1}})\] Hence \[\Delta P'>\Delta P\]
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