question_answer

\[\int{\frac{dx}{{{x}^{2}}\sqrt{4-{{x}^{2}}}}}\]  is equal to _______.

A)  \[\frac{1}{4}\,\,\left( \frac{\sqrt{4-{{x}^{2}}}}{x} \right)+C\]    

B)  \[\frac{1}{2}\,\,\left( \frac{\sqrt{4-{{x}^{2}}}}{x} \right)+C\]

C)  \[\frac{-1}{4}\,\,\left( \frac{\sqrt{4-{{x}^{2}}}}{x} \right)+C\]   

D)  \[\frac{-1}{2}\,\,\left( \frac{\sqrt{4-{{x}^{2}}}}{x} \right)+C\]

E)  None of these