question_answer

The point of intersection of the lines\[\frac{x+1}{3}=\frac{y+3}{5}=\frac{z+5}{7}\] and \[\frac{x-2}{1}=\frac{y-4}{3}=\frac{z-6}{5}\] is

A)  \[\left( \frac{1}{2},\,\,\frac{1}{2},\,\,\frac{-3}{2} \right)\]             

B)  \[\left( \frac{-1}{2},\,\,\frac{-1}{2},\,\,\frac{3}{2} \right)\]

C)  \[\left( \frac{1}{2},\,\,\frac{-1}{2},\,\,\frac{-3}{2} \right)\]

D)  \[\left( \frac{-1}{2},\,\,\frac{1}{2},\,\,\frac{3}{2} \right)\]

E)  None of these