question_answer

The point of intersection of the lines \[\frac{x+1}{3}=\frac{y+3}{5}=\frac{z+5}{7}\] and \[\frac{x-2}{1}=\frac{y-4}{3}=\frac{z-6}{5}\]is

A)  \[\left( \frac{1}{2},\frac{1}{2},-\frac{3}{2} \right)\]                     

B)  \[\left( -\frac{1}{2},-\frac{1}{2},\frac{3}{2} \right)\]

C)  \[\left( \frac{1}{2},-\frac{1}{2},-\frac{3}{2} \right)\]        

D)  \[\left( -\frac{1}{2},\frac{1}{2},\frac{3}{2} \right)\]

E)  None of these