Answer:
\[\frac{5}{3}+\frac{11}{2}+\frac{-9}{4}+\frac{-8}{3}+\frac{-7}{2}=\left( \frac{5}{3}+\frac{-8}{3} \right)+\left( \frac{11}{2}+\frac{-7}{2} \right)+\left( \frac{-9}{4} \right)\]\[=\frac{5+(-8)}{3}+\frac{11+(-7)}{2}+\frac{-9}{4}\] \[=-\frac{3}{3}+\frac{4}{2}+\frac{-9}{4}\] \[=1+\frac{(-9)}{4}\] \[=\frac{1\times 4+(-9)}{4}=\frac{4-9}{4}\] \[=\frac{-5}{4}.\]
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