question_answer

How many bricks of size 22 cm \[\times \text{ }10\]cm \[\times \text{ 7}\] cm are required to construct a wall 11 m long, 3.5 m high and 40 cm thick, if the cement and sand used in the construction occupy \[{{\left( \frac{1}{10} \right)}^{th}}\]part of the wall?

Answer:

Volume of a brick = 22 cm \[\times \] 10 cm \[\times \] 7 cm

\[=\text{ }1540\text{ }c{{m}^{3}}\]

Dimensions of wall

l = 11 m, b = 3.5 m,

h = 40 cm = 0.4 m

Volume of wall \[=11\times 3.5\times 0.4\]

\[=\text{ }15.4\text{ }{{m}^{3}}\]

\[=\text{ }15.4\times 1000000\text{ }c{{m}^{3}}\]

\[=\text{ }15400000\text{ }c{{m}^{3}}\]

Since, cement and sand occupy \[{{\left( \frac{1}{10} \right)}^{th}}\] part of the wall

So, new volume \[=\text{ }15400000\text{ }\times \frac{1}{10}\]

\[=\text{ }1540000\text{ }c{{m}^{3}}\]

\[No.\text{ }of\text{ }bricks\text{ }=\frac{1540000}{1540}\]

= 1000