question_answer

If the division \[N\div 5\] leaves a remainder of 1 what might be the one?s digit of N?

Answer:

If remainder = 1, then the one?s digit of ?N? must be either 1 or 6.

\[({{2}^{5}}\div {{2}^{8}})\times {{2}^{-7}}=\left( \frac{{{2}^{5}}}{{{2}^{8}}} \right)\times {{2}^{-7}}\]