Factorise the following: |
(a) \[{{x}^{2}}+9x+20\] |
(b) \[{{p}^{2}}-13p-30~\] |
Answer:
(a) \[{{x}^{2}}+9x+20={{x}^{2}}+\left( 5+4 \right)x+20\] \[={{x}^{2}}+5x+4x+20\] \[=\text{ }x\left( x+5 \right)+4\left( x+5 \right)\] \[=\left( x+5 \right)\left( x+4 \right)\] (b) \[{{p}^{2}}13p30={{p}^{2}}\left( 152 \right)p30\] \[={{p}^{2}}15p+2p30\] \[=\text{ }p\left( p15 \right)+2\left( p15 \right)\] \[=\left( p15 \right)\left( p+2 \right)\]
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