question_answer

Find:

(a) \[5\times 2\frac{3}{7}\]

(b) \[1\frac{4}{9}\times 6\]

Answer:

(a)  \[5\times 2\frac{3}{7}=5\times \frac{2\times 7+3}{7}\]

=\[5\times \frac{14+3}{7}\]

=\[5\times \frac{17}{7}=\frac{5\times 17}{7}\]

=\[\frac{85}{7}=12\frac{1}{7}\]

(b) \[1\frac{4}{9}\times 6=\frac{1\times 9+4}{9}\times 6\]

\[=\frac{9+4}{9}\times 6\]

=\[\frac{13}{9}\times 6=\frac{13\times 6}{9}\]

\[=\frac{78}{9}\]

Dividing the numerator and denominator by 3, we get

\[\frac{26}{3}=8\frac{2}{3}\]