question_answer

A polyhedron is having 8 vertices and 12 edges. How many faces of it are there?

Answer:

Number of vertices (V)=8

Number of edges (E) = 12.

Let the number of faces be F

Now, using Euler's formula

F+V=E+2

We have,

F + 8 = 12 + 2

F + 8 = 14

\[F=14-8~\]

F = 6.

Thus, the required number of faces =6