question_answer

Construct an isosceles right triangle such that its hypotenuse is 5.5 cm.

Answer:

Steps of Construction:

(a) Draw AC = 5 - 5 cm.

(b) At A, construct\[\angle CAX=45{}^\circ \].

(c) At C, construct\[\angle ACY=45{}^\circ \], such that \[\overline{CY}\]meets \[\overline{AX}\]at B.

Then, ABC is the required isosceles triangle, in which AB = CB and\[\angle B=90{}^\circ \].