6th Class Mathematics Sample Paper Mathematics Sample Paper-7

  • question_answer
    Find the perimeter of the following rectangles:
    Sr. No Length of Rectangle Breadth of Rectangle Perimeter By adding all the sides Perimeter by 2 \[\mathbf{\times }\] (length \[\mathbf{\times }\] breadth)
    (i) 25 cm 12 cm \[25\,\,cm+12\text{ }cm+\]\[25\text{ }cm+12\text{ }cm\] \[=74\text{ }cm\] \[=2\times (25\,\,cm\]\[+12\,\,cm)\] \[=2\times (37\,\,cm)\] \[=74cm\]
    (ii) 0.5 m 0.25 m    
    (iii) 18 cm 15 cm    
    (iv) 10.5 cm 8.5 cm    

    Answer:

               
    Sr. No Length of Rectangles Breadth of Rectangle Perimeter by adding all the sides Perimeter by 2 \[\times \] (length \[\times \] breadth)
    (i) 0.5 cm 0.25 m = 0.5 m + 0.25 m + 0.5 m + 0.25 m = 1.50 m                                     = 2 \[\times \] (0.5 m + 0.25 m) = 2 \[\times \] (0.75 m) = 1.50 m                      
    (ii) 18 cm 15 cm = 18 cm + 15 cm + 18 cm + 15 cm = 66 cm                                   = 2 \[\times \] (18 cm + 15 cm) = 2 \[\times \] (33 cm) = 66 cm                        
    (iii) 10.5 cm 8.5 cm = 10.5 cm + 8.5 cm + 10.5 cm + 8.5 cm = 38 cm                             = 2 \[\times \] (10.5 cm + 8.5 cm) = 2 \[\times \] (19 cm) = 38 cm                        
    From above example, it is clear the perimeter of a rectangle = 2 \[\times \] (length + breadth)


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