Answer:
\[\left( -\frac{3}{2}\times \frac{4}{5} \right)\div \left( \frac{9}{5}\times \frac{-10}{3} \right) \left( \frac{1}{2}\times \frac{3}{4} \right)=\left( -\frac{3\times 2}{5} \right)\div (3\times -2) \left( \frac{3}{8} \right)\] \[=-\frac{6}{5}\div (-6)-\frac{3}{8}\] \[=-\frac{6}{5}\times -\frac{1}{6}-\frac{3}{8}\] \[=\frac{1}{5}-\frac{3}{8}\] \[=\frac{8-15}{40}=\frac{-7}{40}\]
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