question_answer

If \[a\cot q+\]\[b\cos ecq=p\] and \[b\cot q+\]\[a\cos ecq=q\], then \[{{p}^{2}}-{{q}^{2}}\]is equal to:

A) \[{{a}^{2}}-{{b}^{2}}\]

B)                    \[{{b}^{2}}-{{a}^{2}}\]

C) \[{{a}^{2}}+{{b}^{2}}\]      

D) \[b-a\]

E) None of these