Answer:
In first case, when shopkeeper found a profit. Cost Price (C.E) =Rs. 10,000 Profit% =10% Selling Price (S.E) =? We know that, \[S.P.=\frac{(100+\Pr ofit%)}{100}\times C.P.\] \[=\left( \frac{100+10}{100} \right)\times 10,000\] S.P. = \[110\times 100\text{ }=\text{ Rs}\text{. }11,000\] Selling price (S.E) of first case =Rs. 11,000 In second case, When shopkeeper found a loss, C.P. =Rs.10, 000 Loss% = 10% S.P. =? We know that, \[S.P.=\frac{(100-loss%)}{100}\times C.P.\] \[=\frac{(100-10)}{100}\times 10,000\] \[=90\times 100\] S.P. =Rs. 9,000 S.P. of second case =Rs. 9,000 According to whole transaction, Total C.E of both cases \[=\text{ }10,000\times 2=Rs.20,000\] Total S.E of both cases = (11,000 + 9,000) =Rs. 20,000 Hence, these is no profit or no loss.
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