8th Class Mathematics Sample Paper Mathematics Sample Paper - 4

  • question_answer
    A shopkeeper bought two TV sets at Rs. 10,000 each. He sold one at a profit 10% and the other at a loss of 10%. Find whether he made an overall profit or loss.

    Answer:

    In first case, when shopkeeper found a profit.
    Cost Price (C.E) =Rs. 10,000
    Profit% =10%
    Selling Price (S.E) =?
    We know that,
    \[S.P.=\frac{(100+\Pr ofit%)}{100}\times C.P.\]
    \[=\left( \frac{100+10}{100} \right)\times 10,000\]
    S.P. = \[110\times 100\text{ }=\text{ Rs}\text{. }11,000\]
    Selling price (S.E) of first case =Rs. 11,000                                                                                                                                   
    In second case,
    When shopkeeper found a loss,
    C.P. =Rs.10, 000
    Loss% = 10%
    S.P. =?
    We know that,                 \[S.P.=\frac{(100-loss%)}{100}\times C.P.\]
    \[=\frac{(100-10)}{100}\times 10,000\]
    \[=90\times 100\]
    S.P. =Rs. 9,000
    S.P. of second case =Rs. 9,000                                                                                                                                                          
    According to whole transaction,
    Total C.E of both cases \[=\text{ }10,000\times 2=Rs.20,000\]
    Total S.E of both cases = (11,000 + 9,000)
    =Rs. 20,000
    Hence, these is no profit or no loss.
     


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