• # question_answer Draw $\angle BAC$or measure $75{}^\circ$and find its line of symmetry.

 So to find the line or symmetry of angle $75{}^\circ$, we use the following steps: Step I: Draw $\overline{AB}$of any length. Step II: Place the centre of the protractor at A and the zero edge along $\overline{AB}$. Step III: Start with zero near B, mark point C at $75{}^\circ$. Step IV: Join AC. $\angle BAC$is the required angle of measure $75{}^\circ$. Step V: With A as centre and using compasses, draw an arc that cuts both rays of $\angle A$ at P and $Q$. Step VI: With P as centre, draw (in the interior of $\angle A$ an arc whose radius is more than half of the length of$PQ$). Step VII: With the same radius and with Q as centre, draw another arc in the interior of $\angle A$. Let the two arcs intersect at D. Step VIII: Join AD, then is $\overline{AD}$the required bisector of $\angle A$, i.e., AD is the line of symmetry of an angle of measure $75{}^\circ$.