question_answer

In a village, there are 8 water tanks to collect rain water. On a particular day, \[x\,L\]of rain water is collected per tank. If 100 L of water was already there in one of the tanks. What is the total amount of water in the tanks on that day?

Answer:

According to the question Tanks to collect rain water = 8 Rain water is collected per tank (in L) = x Then, total rain water in tanks (in L) = Number of tanks \[\times \] Per tank collected rain water \[=8\times x=8x\]. But in the one tank, already 100 L of water exist, then Total amount of water is given by = 100 + [total rain water in L] \[=100+8x\] or \[(8x+100)\text{ }L\]