| Find the perimeter of the following figures: |
(a)  |
| Perimeter = AB + BC + CD + DA |
| = .... cm + .... cm + .... cm + ....cm = .... |
(b)  |
| Perimeter = AB + BC + CD + DA |
| = .... cm + .... cm + .... cm + .... cm = .... |
(c)  |
| Perimeter = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA |
| =.... cm + .... cm + .... cm + .... cm + .... cm + .... cm + .... cm + .... cm + .... cm + .... cm + .... cm + .... cm = .... |
(d)  |
| Perimeter = AB + BC + CD + DE + EF + FA |
| = .... cm + .... cm + .... cm + .... cm + .... cm + .... cm = .... |
| Note: For finding the perimeter of any closed figure made up entirely of line segments, simply find the sum of the lengths of all the sides (which are line segments). |
Answer:
(a) Perimeter \[=AB+BC+CD+DA\]
\[=40\text{ }cm+10\text{ }cm+40\text{ }cm\text{ }+\text{ }10\text{ }cm\]
\[=100\text{ }cm\]
(b) Perimeter \[=AB+BC+CD+DA\]
\[=5cm+5cm+5cm+5cm\]
\[=20\text{ }cm\]
(c) Perimeter \[=AB+BC+CD+DE\text{ }+\text{ }EF\]
\[+FG+GH+HI+IJ+JK+KL+LA\]
\[=(1+3+3+1+3+3+1+3+3+1+3+3)\text{ }cm\]
\[=28\text{ }cm\]
(d) Perimeter \[=AB+BC+CD+DE+EF+FA\]
\[=100\text{ }m+120\text{ }m+90\text{ }m+45\text{ }m+60\text{ }m+80\text{ }m\]
\[=495\text{ }m\]
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