question_answer

Give a proper fraction:

(a) Whose numerator is 5 and denominator is 7.

(b) Whose denominator is 9 and numerator is 5.

(c) Whose numerator and denominator add up to 10. How many fractions of this kind can you make?

(d) Whose denominator is 4 more than the numerator. Give any five. How many more can you make?

Answer:

(a)        Numerator = 5, Denominator = 7

So, the fraction \[=\frac{5}{7}\]

(b)        Numerator = 5, Denominator = 9

So, the fraction \[=\frac{5}{9}\]

(c) Possible   pairs   of   numerator   and denominator which add up to 10 are 0, 10; 1, 9; 2, 8; 3, 7; 4, 6 which give us proper fractions: \[\frac{0}{10},\frac{1}{9},\frac{2}{8},\frac{3}{7},\frac{4}{6}\]  These are 5 in number.

(d) 5 proper fractions in which denominator is 4 more than the numerator are  \[\frac{0}{4},\frac{1}{5},\frac{2}{6},\frac{3}{7},\frac{5}{9}\]

We can make an infinite number of proper fractions according to the given conditions.